What is the domain of f(x)=2ln(3)-1/2 ln(x^2+1) ?

The domain of f(x)=2ln(3)-1/2 ln(x^2+1) is -infinity <x<infinity

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domain of f(x)=2ln(3)-1/2 ln(x^2+1)

domain

f (x) = 2 ln (3) - \frac{1}{2} ln (x^{2} + 1)

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find positive values for logs:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

ln (9) + 9 ln (x) - 6 ln (y)

- lo g_{10} (1.7 \cdot 1 0^{- 8})

ln (\frac{x ^{2} 3 x - 2}{( x + 1 ) ^{2}})

ln (x^{7} (x + 9)^{5} (x^{2} + 9)^{7})

ln (t) + 7 ln (r) - 6 ln (t)

What is the domain of f(x)=2ln(3)-1/2 ln(x^2+1) ?
The domain of f(x)=2ln(3)-1/2 ln(x^2+1) is -infinity <x<infinity