What is 0.935-(0.592)/2 log_{10}((0.2)/(0.1^2)) ?

The solution to 0.935-(0.592)/2 log_{10}((0.2)/(0.1^2)) is 187/200-37/125 log_{10}(20)

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simplify 0.935-(0.592)/2 log_{10}((0.2)/(0.1^2))

simplify

0.935 - \frac{0.592}{2} lo g_{10} (\frac{0.2}{0. 1 ^{2}})

\frac{187}{200} - \frac{37}{125} lo g_{10} (20)

Decimal Notation

0.54989 \dots

Solution steps

0.935 - \frac{0.592}{2} lo g_{10} (\frac{0.2}{0. 1 ^{2}})

0.935 = \frac{187}{200}

= \frac{187}{200} - \frac{0.592}{2} lo g_{10} (\frac{0.2}{0. 1 ^{2}})

\frac{0.592}{2} = \frac{592}{2000}

= \frac{187}{200} - \frac{592}{2000} lo g_{10} (\frac{0.2}{0. 1 ^{2}})

\frac{592}{2000} lo g_{10} (\frac{0.2}{0. 1 ^{2}}) = \frac{37}{125} lo g_{10} (20)

= \frac{187}{200} - \frac{37}{125} lo g_{10} (20)

f (x) = ln (\frac{3 ^{x} 6 ^{3 x}}{2 ^{2 x}})

lo g_{b} (\frac{x y ^{3}}{w ^{3} z})

\frac{1}{5} ln (\frac{5}{4})

- ln (\frac{5}{9})

ln (\frac{14}{5})

What is 0.935-(0.592)/2 log_{10}((0.2)/(0.1^2)) ?
The solution to 0.935-(0.592)/2 log_{10}((0.2)/(0.1^2)) is 187/200-37/125 log_{10}(20)