What is ln(((1+e^x))/((1-e^x))) ?

The solution to ln(((1+e^x))/((1-e^x))) is ln(1+e^x)-ln(1-e^x)

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simplify ln(((1+e^x))/((1-e^x)))

simplify

ln (\frac{( 1 + e ^{x} )}{( 1 - e ^{x} )})

ln (1 + e^{x}) - ln (1 - e^{x})

Solution steps

ln (\frac{( 1 + e ^{x} )}{( 1 - e ^{x} )})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{( 1 + e ^{x} )}{( 1 - e ^{x} )}) = ln ((1 + e^{x})) - ln ((1 - e^{x}))

= ln (e^{x} + 1) - ln (- e^{x} + 1)

lo g_{b} (\frac{a ^{2} b ^{3}}{c ^{4} m})

4 ln (x) + 4 ln (y)

lo g_{8} (2 x^{3})

lo g_{10} (9 x)

lo g_{b} (\frac{4}{c})

What is ln(((1+e^x))/((1-e^x))) ?
The solution to ln(((1+e^x))/((1-e^x))) is ln(1+e^x)-ln(1-e^x)