What is log_{2}(infinity) ?

The solution to log_{2}(infinity) is log_{2}(f)+3log_{2}(i)+log_{2}(t)+2log_{2}(n)+log_{2}(y)

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simplify log_{2}(infinity)

simplify

lo g_{2} (in f ini t y)

lo g_{2} (f) + 3 lo g_{2} (i) + lo g_{2} (t) + 2 lo g_{2} (n) + lo g_{2} (y)

Solution steps

lo g_{2} (in f ini t y)

Simplify

in f ini t y : f i^{3} t n^{2} y

= lo g_{2} (f i^{3} t n^{2} y)

Apply log rule:

lo g_{a} (x y) = lo g_{a} (x) + lo g_{a} (y)

lo g_{2} (f i^{3} t n^{2} y) = lo g_{2} (f) + lo g_{2} (i^{3}) + lo g_{2} (t) + lo g_{2} (n^{2}) + lo g_{2} (y)

= lo g_{2} (f) + lo g_{2} (i^{3}) + lo g_{2} (t) + lo g_{2} (n^{2}) + lo g_{2} (y)

lo g_{2} (i^{3}) = 3 lo g_{2} (i)

lo g_{2} (n^{2}) = 2 lo g_{2} (n)

= lo g_{2} (f) + 3 lo g_{2} (i) + lo g_{2} (t) + 2 lo g_{2} (n) + lo g_{2} (y)

\frac{1}{2} lo g_{b} (x) + 3 lo g_{b} (y) - lo g_{b} (z)

2.5 ln (2 x^{- 1}) - 4 + 0.1 x^{1.5}

ln (x^{2} y^{2} z^{2})

lo g_{10} (13 c d)

ln (x) + ln (x - 2) + ln (4 x)

What is log_{2}(infinity) ?
The solution to log_{2}(infinity) is log_{2}(f)+3log_{2}(i)+log_{2}(t)+2log_{2}(n)+log_{2}(y)