What is expand ln((x^2+1)(x-1)) ?

The solution to expand ln((x^2+1)(x-1)) is ln(x^2+1)+ln(x-1)

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expand ln((x^2+1)(x-1))

expand

ln ((x^{2} + 1) (x - 1))

ln (x^{2} + 1) + ln (x - 1)

Solution steps

ln ((x^{2} + 1) (x - 1))

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

ln ((x^{2} + 1) (x - 1)) = ln (x^{2} + 1) + ln (x - 1)

= ln (x^{2} + 1) + ln (x - 1)

lo g_{8} (7 x^{4})

lo g_{9} (u^{2})

lo g_{4} (2 x^{2} + x - 21) - lo g_{4} (x - 3)

4 lo g_{a} (y) - \frac{1}{2} lo g_{a} (x) + 3 lo g_{a} (w)

f (x) = \frac{1}{3} ln (x + 8) + \frac{1}{2} ln (x - 1)

What is expand ln((x^2+1)(x-1)) ?
The solution to expand ln((x^2+1)(x-1)) is ln(x^2+1)+ln(x-1)