What is ln(((70-95))/((5-95)(1.9958))) ?

The solution to ln(((70-95))/((5-95)(1.9958))) is ln(-25)-ln(-90)-ln(1.9958)

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simplify ln(((70-95))/((5-95)(1.9958)))

simplify

ln (\frac{( 70 - 95 )}{( 5 - 95 ) ( 1.9958 )})

ln (- 25) - ln (- 90) - ln (1.9958)

Solution steps

ln (\frac{( 70 - 95 )}{( 5 - 95 ) ( 1.9958 )})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{( 70 - 95 )}{( 5 - 95 ) ( 1.9958 )}) = ln ((70 - 95)) - ln ((5 - 95) (1.9958))

= ln (70 - 95) - ln (1.9958 (5 - 95))

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

ln ((5 - 95) \cdot 1.9958) = ln (5 - 95) + ln (1.9958)

= ln (70 - 95) - (ln (5 - 95) + ln (1.9958))

Subtract the numbers:

70 - 95 = - 25

= ln (- 25) - (ln (5 - 95) + ln (1.9958))

Subtract the numbers:

5 - 95 = - 90

= ln (- 25) - (ln (- 90) + ln (1.9958))

- (ln (- 90) + ln (1.9958)) : - ln (- 90) - ln (1.9958)

= ln (- 25) - ln (- 90) - ln (1.9958)

ln (23) - ln (7)

lo g_{3} (\frac{1}{9} a^{3} b)

5 (lo g_{5} (3) + lo g_{5} (b)) - lo g_{5} (4)

- lo g_{10} (4 \times 1 0^{- 4})

What is ln(((70-95))/((5-95)(1.9958))) ?
The solution to ln(((70-95))/((5-95)(1.9958))) is ln(-25)-ln(-90)-ln(1.9958)