What are the solutions to the equation 6x^2+31x=17 ?

The solutions to the equation 6x^2+31x=17 are x= 1/2 ,x=-17/3

Find the zeros of 6x^2+31x=17

The zeros of 6x^2+31x=17 are x= 1/2 ,x=-17/3

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6 x^{2} + 31 x = 17

x = \frac{1}{2}, x = - \frac{17}{3}

Solution steps

6 x^{2} + 31 x = 17

Move

17

to the left side

6 x^{2} + 31 x - 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 31 \pm 3 1 ^{2} - 4 \cdot 6 ( - 17 )}{2 \cdot 6}

3 1^{2} - 4 \cdot 6 (- 17) = 37

x_{1, 2} = \frac{- 31 \pm 37}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 31 + 37}{2 \cdot 6}, x_{2} = \frac{- 31 - 37}{2 \cdot 6}

x = \frac{- 31 + 37}{2 \cdot 6} : \frac{1}{2}

x = \frac{- 31 - 37}{2 \cdot 6} : - \frac{17}{3}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{17}{3}

4 x (x + 5) - 3 (x + 5)

4 q < 8

(7 i)^{2}

x^{2} - 10 = 0

lo g_{10} (0.01) = x

What are the solutions to the equation 6x^2+31x=17 ?
The solutions to the equation 6x^2+31x=17 are x= 1/2 ,x=-17/3
Find the zeros of 6x^2+31x=17
The zeros of 6x^2+31x=17 are x= 1/2 ,x=-17/3