What is log_{10}(1/(sqrt(x^2+36))) ?

The solution to log_{10}(1/(sqrt(x^2+36))) is -log_{10}(sqrt(x^2+36))

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simplify log_{10}(1/(sqrt(x^2+36)))

simplify

lo g_{10} (\frac{1}{x ^{2} + 36})

- lo g_{10} (x^{2} + 36)

Solution steps

lo g_{10} (\frac{1}{x ^{2} + 36})

Simplify

\frac{1}{x ^{2} + 36} : (x^{2} + 36)^{- 1}

= lo g_{10} ((x^{2} + 36)^{- 1})

Apply log rule

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x), assuming x > 0

lo g_{10} ((x^{2} + 36)^{- 1}) = - 1 \cdot lo g_{10} (x^{2} + 36)

= - 1 \cdot lo g_{10} (x^{2} + 36)

Apply rule:

1 \cdot a = a

= - lo g_{10} (x^{2} + 36)

ln (z) + ln (11 y)

2 ln (\frac{e}{y}) - ln (x^{4} y) + e^{- 3 l n (y)}

3 lo g_{10} (9) + 3 lo g_{10} (x)

ln (p^{x} (1 - p)^{n - x})

3.3 (lo g_{10} (1601.01) - lo g_{10} (3))

What is log_{10}(1/(sqrt(x^2+36))) ?
The solution to log_{10}(1/(sqrt(x^2+36))) is -log_{10}(sqrt(x^2+36))