What is log_{3}((\sqrt[3]{5})/(s^2x)) ?

The solution to log_{3}((\sqrt[3]{5})/(s^2x)) is log_{3}(\sqrt[3]{5})-2log_{3}(s)-log_{3}(x)

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simplify log_{3}((\sqrt[3]{5})/(s^2x))

simplify

Solution steps

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

Simplify

lo g_{3} (s^{2} x) : 2 lo g_{3} (s) + lo g_{3} (x)

Apply the distributive law:

- (a + b) = - a - b

- (2 lo g_{3} (s) + lo g_{3} (x)) = - 2 lo g_{3} (s) - lo g_{3} (x)

lo g_{4} (3 x^{2})

ln (\frac{e ^{t}}{t + 1})

ln (x^{2}) + 3 ln (y)

\frac{9}{2} + ln ∣ 3 ∣ - 2 + ln ∣ 2 ∣

lo g_{10} (\frac{x ^{6} y ^{8}}{z ^{10}})

What is log_{3}((\sqrt[3]{5})/(s^2x)) ?
The solution to log_{3}((\sqrt[3]{5})/(s^2x)) is log_{3}(\sqrt[3]{5})-2log_{3}(s)-log_{3}(x)