What are the solutions to the equation x^2+4x=-3 ?

The solutions to the equation x^2+4x=-3 are x=-1,x=-3

Find the zeros of x^2+4x=-3

The zeros of x^2+4x=-3 are x=-1,x=-3

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x^{2} + 4 x = - 3

x = - 1, x = - 3

Solution steps

x^{2} + 4 x = - 3

Move

3

to the left side

x^{2} + 4 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 3 = 2

x_{1, 2} = \frac{- 4 \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2}{2 \cdot 1}, x_{2} = \frac{- 4 - 2}{2 \cdot 1}

x = \frac{- 4 + 2}{2 \cdot 1} : - 1

x = \frac{- 4 - 2}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = - 1, x = - 3

x^{3} + 2 x^{2} + 2 x + 4

x^{2} + 4 x - 21

3 x - 9 x^{2}

2 (4 v - 5) = 70

What are the solutions to the equation x^2+4x=-3 ?
The solutions to the equation x^2+4x=-3 are x=-1,x=-3
Find the zeros of x^2+4x=-3
The zeros of x^2+4x=-3 are x=-1,x=-3