What is ln((12)/(\frac{7.02){0.0445}}) ?

The solution to ln((12)/(\frac{7.02){0.0445}}) is ln(12)-ln(7.02)+ln(0.0445)

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simplify ln((12)/(\frac{7.02){0.0445}})

simplify

ln (\frac{12}{\frac{7.02}{0.0445}})

ln (12) - ln (7.02) + ln (0.0445)

Decimal Notation

- 2.57612 \dots

Solution steps

ln (\frac{12}{\frac{7.02}{0.0445}})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{12}{\frac{7.02}{0.0445}}) = ln (12) - ln (\frac{7.02}{0.0445})

= ln (12) - ln (\frac{7.02}{0.0445})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{7.02}{0.0445}) = ln (7.02) - ln (0.0445)

= ln (12) - (ln (7.02) - ln (0.0445))

- (ln (7.02) - ln (0.0445)) : - ln (7.02) + ln (0.0445)

= ln (12) - ln (7.02) + ln (0.0445)

5 lo g_{4} (a) + 6 lo g_{4} (b) - \frac{1}{3} lo g_{4} (7 c)

lo g_{10} (y) + lo g_{10} (z)

lo g_{4} (\frac{x - 2}{x ^{5}})

\frac{ln ( 4 )}{ln ( 4 ) - ln ( 5 )}

What is ln((12)/(\frac{7.02){0.0445}}) ?
The solution to ln((12)/(\frac{7.02){0.0445}}) is ln(12)-ln(7.02)+ln(0.0445)