What is the domain of f(x)=2ln(5x^2)-ln(2x^2) ?

The domain of f(x)=2ln(5x^2)-ln(2x^2) is x 0

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domain of f(x)=2ln(5x^2)-ln(2x^2)

domain

f (x) = 2 ln (5 x^{2}) - ln (2 x^{2})

x < 0 or x > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

Find positive values for logs:

x < 0 or x > 0

The function domain

x < 0 or x > 0

1.1 - \frac{0.0257}{2} ln (\frac{0.25}{1})

ln (\frac{2 ^{- 4}}{3 ^{- 3} 5 ^{- 1}})

ln (\frac{78}{175}) 6

lo g_{10} (\frac{8 z}{11})

\frac{1}{2} lo g_{10} (a) + \frac{1}{2} lo g_{10} (b)

What is the domain of f(x)=2ln(5x^2)-ln(2x^2) ?
The domain of f(x)=2ln(5x^2)-ln(2x^2) is x<0\lor x>0