What is ln(xyz)+(i+j+k) ?

The solution to ln(xyz)+(i+j+k) is (ln(xyz)+j+k)+i

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simplify ln(xyz)+(i+j+k)

simplify

ln (x yz) + (i + j + k)

(ln (x yz) + j + k) + i

Solution steps

ln (x yz) + (i + j + k)

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

ln (x yz) = ln (x) + ln (y) + ln (z)

= ln (x) + ln (y) + ln (z) + (k + j + i)

Remove parentheses:

(a) = a

= ln (x) + ln (y) + ln (z) + i + j + k

Rewrite

ln (x) + ln (y) + ln (z) + i + j + k

in standard complex form:

(ln (x yz) + j + k) + i

= (ln (x yz) + j + k) + i

ln (2 e) \cdot \frac{3}{59}

lo g_{10} (8) + lo g_{10} (5) + lo g_{10} (3)

lo g_{6} (36 x^{3})

lo g_{10} (\frac{1}{2} x)

ln^{2} (x) - ln^{2} (y)