What is log_{10}((x^2-x-12)/x) ?

The solution to log_{10}((x^2-x-12)/x) is log_{10}(x^2-x-12)-log_{10}(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify log_{10}((x^2-x-12)/x)

simplify

lo g_{10} (\frac{x ^{2} - x - 12}{x})

lo g_{10} (x^{2} - x - 12) - lo g_{10} (x)

Solution steps

lo g_{10} (\frac{x ^{2} - x - 12}{x})

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

lo g_{10} (\frac{x ^{2} - x - 12}{x}) = lo g_{10} (x^{2} - x - 12) - lo g_{10} (x)

= lo g_{10} (x^{2} - x - 12) - lo g_{10} (x)

lo g_{2} (10) - lo g_{2} (5) + lo g_{2} (11)

lo g_{10} (y) + lo g_{10} (18)

ln (\frac{13 x ^{8}}{y ^{5}})

lo g_{3} (\frac{1}{2}) + (\frac{1}{2})^{2}

What is log_{10}((x^2-x-12)/x) ?
The solution to log_{10}((x^2-x-12)/x) is log_{10}(x^2-x-12)-log_{10}(x)