What is 2log_{2}(3)-log_{2}(5) ?

The solution to 2log_{2}(3)-log_{2}(5) is log_{2}(9/5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 2log_{2}(3)-log_{2}(5)

simplify

2 lo g_{2} (3) - lo g_{2} (5)

lo g_{2} (\frac{9}{5})

Decimal Notation

0.84799 \dots

Solution steps

2 lo g_{2} (3) - lo g_{2} (5)

Apply log rule:

b \cdot lo g_{a} (x) = lo g_{a} (x^{b})

2 lo g_{2} (3) = lo g_{2} (3^{2})

= lo g_{2} (3^{2}) - lo g_{2} (5)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{2} (3^{2}) - lo g_{2} (5) = lo g_{2} (\frac{3 ^{2}}{5})

= lo g_{2} (\frac{3 ^{2}}{5})

3^{2} = 9

= lo g_{2} (\frac{9}{5})

lo g_{10} (2) + lo g_{10} (11)

lo g_{7} (9) - lo g_{7} (8)

ln (2) + 2 ln (x) + 2 ln (x^{2} + 2)

- \frac{ln ( 531441 g )}{3 ln ( 3 ) - ln ( g )}

lo g_{2} (2 x)

What is 2log_{2}(3)-log_{2}(5) ?
The solution to 2log_{2}(3)-log_{2}(5) is log_{2}(9/5)