What is log_{10}(80)+log_{10}(6) ?

The solution to log_{10}(80)+log_{10}(6) is log_{10}(480)

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simplify log_{10}(80)+log_{10}(6)

simplify

lo g_{10} (80) + lo g_{10} (6)

lo g_{10} (480)

Decimal Notation

2.68124 \dots

Solution steps

lo g_{10} (80) + lo g_{10} (6)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (80) + lo g_{10} (6) = lo g_{10} (80 \cdot 6)

= lo g_{10} (80 \cdot 6)

Multiply the numbers:

80 \cdot 6 = 480

= lo g_{10} (480)

ln (\frac{1}{x} x^{4})

- lo g_{10} (3.39880433 \times 1 0^{- 5})

lo g_{10} (\frac{7 z}{10})

ln (\frac{7 y}{5 z})

lo g_{4} (\frac{4}{x})

What is log_{10}(80)+log_{10}(6) ?
The solution to log_{10}(80)+log_{10}(6) is log_{10}(480)