What is log_{10}(x)+log_{10}(2x-1) ?

The solution to log_{10}(x)+log_{10}(2x-1) is log_{10}(x(2x-1))

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simplify log_{10}(x)+log_{10}(2x-1)

simplify

lo g_{10} (x) + lo g_{10} (2 x - 1)

lo g_{10} (x (2 x - 1))

Solution steps

lo g_{10} (x) + lo g_{10} (2 x - 1)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (x) + lo g_{10} (2 x - 1) = lo g_{10} (x (2 x - 1))

= lo g_{10} (x (2 x - 1))

lo g_{8} (\frac{w ^{3}}{v})

ln (4) + ln (3 x)

cos (x) - ln (2 x)

(lo g_{5} (x + y) + 2 lo g_{5} (y)) - 3 lo g_{5} (x)

What is log_{10}(x)+log_{10}(2x-1) ?
The solution to log_{10}(x)+log_{10}(2x-1) is log_{10}(x(2x-1))