What is 6/(log_{10)(0.593)-log_{10}(0.451)} ?

The solution to 6/(log_{10)(0.593)-log_{10}(0.451)} is 6/(log_{10)(593/451)}

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simplify 6/(log_{10)(0.593)-log_{10}(0.451)}

simplify

\frac{6}{lo g _{10} ( 0.593 ) - lo g _{10} ( 0.451 )}

\frac{6}{lo g _{10} ( \frac{593}{451} )}

Decimal Notation

50.47184 \dots

Solution steps

\frac{6}{lo g _{10} ( 0.593 ) - lo g _{10} ( 0.451 )}

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (0.593) - lo g_{10} (0.451) = lo g_{10} (\frac{0.593}{0.451})

= \frac{6}{lo g _{10} ( \frac{0.593}{0.451} )}

\frac{0.593}{0.451} = \frac{593}{451}

= \frac{6}{lo g _{10} ( \frac{593}{451} )}

7 lo g_{5} (x) + 3 lo g_{5} (y^{4})

ln (x^{5})

\frac{1}{2} [3 ln (e) + ln (x) - ln (y)]

- lo g_{10} (1.8 (1 0^{- 5}))

ln ((sin (x))^{- l n (x)})

What is 6/(log_{10)(0.593)-log_{10}(0.451)} ?
The solution to 6/(log_{10)(0.593)-log_{10}(0.451)} is 6/(log_{10)(593/451)}