What is log_{7}(2x)+log_{7}(2)+5 ?

The solution to log_{7}(2x)+log_{7}(2)+5 is log_{7}(4x)+5

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simplify log_{7}(2x)+log_{7}(2)+5

simplify

lo g_{7} (2 x) + lo g_{7} (2) + 5

lo g_{7} (4 x) + 5

Solution steps

lo g_{7} (2 x) + lo g_{7} (2) + 5

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{7} (2 x) + lo g_{7} (2) = lo g_{7} (2 x \cdot 2)

= lo g_{7} (2 x \cdot 2) + 5

Simplify

2 x \cdot 2 : 4 x

= lo g_{7} (4 x) + 5

lo g_{5} (6) + lo g_{5} (x)

ln (\frac{- \frac{1}{2}}{- 1}) - ln (- 1)

1.296 x - 0.00036 x^{2} = 0

a, a^{2} + b^{2} = c^{2}

x^{2} - 20 x + 12 = 0

What is log_{7}(2x)+log_{7}(2)+5 ?
The solution to log_{7}(2x)+log_{7}(2)+5 is log_{7}(4x)+5