What is the answer to 4(y+1)+y=8(y-1)+6 ?

The answer to 4(y+1)+y=8(y-1)+6 is y=2

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4(y+1)+y=8(y-1)+6

4 (y + 1) + y = 8 (y - 1) + 6

y = 2

Solution steps

4 (y + 1) + y = 8 (y - 1) + 6

Expand

4 (y + 1) + y : 5 y + 4

Expand

8 (y - 1) + 6 : 8 y - 2

5 y + 4 = 8 y - 2

Move

4

to the right side

5 y = 8 y - 6

Move

8 y

to the left side

- 3 y = - 6

Divide both sides by

- 3

y = 2

2 x + 7 x + 3

16 h^{2} - 121 k^{2}

7 x - 7 = 3 x + 9

(6 + 8 i)^{2}

26

What is the answer to 4(y+1)+y=8(y-1)+6 ?
The answer to 4(y+1)+y=8(y-1)+6 is y=2
Solve for y: 4(y+1)+y=8(y-1)+6
The solution is y=2