What are the solutions to the equation solvefor r,x^2+y^2=r^2 ?

The solutions to the equation solvefor r,x^2+y^2=r^2 are r=sqrt(x^2+y^2),r=-sqrt(x^2+y^2)

Find the zeros of solvefor r,x^2+y^2=r^2

The zeros of solvefor r,x^2+y^2=r^2 are r=sqrt(x^2+y^2),r=-sqrt(x^2+y^2)

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solve for

r, x^{2} + y^{2} = r^{2}

r = x^{2} + y^{2}, r = - x^{2} + y^{2}

Solution steps

x^{2} + y^{2} = r^{2}

Switch sides

r^{2} = x^{2} + y^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = x^{2} + y^{2}, r = - x^{2} + y^{2}

x^{2} - 4 x

r, v = π r^{2} h

5 x^{2} - 60 x = 0

x^{2} + 6 x

r, v = \frac{1}{3} π r^{2} h

What are the solutions to the equation solvefor r,x^2+y^2=r^2 ?
The solutions to the equation solvefor r,x^2+y^2=r^2 are r=sqrt(x^2+y^2),r=-sqrt(x^2+y^2)
Find the zeros of solvefor r,x^2+y^2=r^2
The zeros of solvefor r,x^2+y^2=r^2 are r=sqrt(x^2+y^2),r=-sqrt(x^2+y^2)