What are the solutions to the equation 2x^2-6x=6x^2-8x ?

The solutions to the equation 2x^2-6x=6x^2-8x are x=0,x= 1/2

Find the zeros of 2x^2-6x=6x^2-8x

The zeros of 2x^2-6x=6x^2-8x are x=0,x= 1/2

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2 x^{2} - 6 x = 6 x^{2} - 8 x

x = 0, x = \frac{1}{2}

Decimal Notation

x = 0, x = 0.5

Solution steps

2 x^{2} - 6 x = 6 x^{2} - 8 x

Move

8 x

to the left side

2 x^{2} + 2 x = 6 x^{2}

Move

6 x^{2}

to the left side

- 4 x^{2} + 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 4 ) \cdot 0}{2 ( - 4 )}

2^{2} - 4 (- 4) \cdot 0 = 2

x_{1, 2} = \frac{- 2 \pm 2}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 2 + 2}{2 ( - 4 )}, x_{2} = \frac{- 2 - 2}{2 ( - 4 )}

x = \frac{- 2 + 2}{2 ( - 4 )} : 0

x = \frac{- 2 - 2}{2 ( - 4 )} : \frac{1}{2}

The solutions to the quadratic equation are:

x = 0, x = \frac{1}{2}

2 x^{2} + 6 = - 34

x^{2} + 2 x

21 x^{2} + 100 = - 5

x^{2} + 4 x

x^{2} - 6 x

What are the solutions to the equation 2x^2-6x=6x^2-8x ?
The solutions to the equation 2x^2-6x=6x^2-8x are x=0,x= 1/2
Find the zeros of 2x^2-6x=6x^2-8x
The zeros of 2x^2-6x=6x^2-8x are x=0,x= 1/2