What are the solutions to the equation solvefor a,x^2+y^2=a^2 ?

The solutions to the equation solvefor a,x^2+y^2=a^2 are a=sqrt(x^2+y^2),a=-sqrt(x^2+y^2)

Find the zeros of solvefor a,x^2+y^2=a^2

The zeros of solvefor a,x^2+y^2=a^2 are a=sqrt(x^2+y^2),a=-sqrt(x^2+y^2)

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solve for

a, x^{2} + y^{2} = a^{2}

a = x^{2} + y^{2}, a = - x^{2} + y^{2}

Solution steps

x^{2} + y^{2} = a^{2}

Switch sides

a^{2} = x^{2} + y^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = x^{2} + y^{2}, a = - x^{2} + y^{2}

x^{2} + 2 x + 5

x^{2} + 7 = - 47

x^{2} + 10 x

x, x^{2} + y^{2} + 4 x - 8 y + 20 = 0

x + 11 = 10 x^{2}

What are the solutions to the equation solvefor a,x^2+y^2=a^2 ?
The solutions to the equation solvefor a,x^2+y^2=a^2 are a=sqrt(x^2+y^2),a=-sqrt(x^2+y^2)
Find the zeros of solvefor a,x^2+y^2=a^2
The zeros of solvefor a,x^2+y^2=a^2 are a=sqrt(x^2+y^2),a=-sqrt(x^2+y^2)