What are the solutions to the equation 3x^2+12x-21=0 ?

The solutions to the equation 3x^2+12x-21=0 are x=-2+sqrt(11),x=-2-sqrt(11)

Find the zeros of 3x^2+12x-21=0

The zeros of 3x^2+12x-21=0 are x=-2+sqrt(11),x=-2-sqrt(11)

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3 x^{2} + 12 x - 21 = 0

x = - 2 + 11, x = - 2 - 11

Decimal Notation

x = 1.31662 \dots, x = - 5.31662 \dots

Solution steps

3 x^{2} + 12 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 3 ( - 21 )}{2 \cdot 3}

1 2^{2} - 4 \cdot 3 (- 21) = 611

x_{1, 2} = \frac{- 12 \pm 6 11}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 12 + 6 11}{2 \cdot 3}, x_{2} = \frac{- 12 - 6 11}{2 \cdot 3}

x = \frac{- 12 + 6 11}{2 \cdot 3} : - 2 + 11

x = \frac{- 12 - 6 11}{2 \cdot 3} : - 2 - 11

The solutions to the quadratic equation are:

x = - 2 + 11, x = - 2 - 11

x, x^{2} y^{2} + \frac{x}{y} = 2 x

x^{2}

4 x^{2} + 5 = 12 x

2 x^{2} + 6 x - 16 = 0

What are the solutions to the equation 3x^2+12x-21=0 ?
The solutions to the equation 3x^2+12x-21=0 are x=-2+sqrt(11),x=-2-sqrt(11)
Find the zeros of 3x^2+12x-21=0
The zeros of 3x^2+12x-21=0 are x=-2+sqrt(11),x=-2-sqrt(11)