What are the solutions to the equation ax^2+bx=0 ?

The solutions to the equation ax^2+bx=0 are x=0,x=-b/a ;\quad a\ne 0

Find the zeros of ax^2+bx=0

The zeros of ax^2+bx=0 are x=0,x=-b/a ;\quad a\ne 0

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a x^{2} + b x = 0

x = 0, x = - \frac{b}{a}; a \neq = 0

Solution steps

a x^{2} + b x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- b \pm b ^{2} - 4 a \cdot 0}{2 a}

Simplify

b^{2} - 4 a \cdot 0 : b

x_{1, 2} = \frac{- b \pm b}{2 a}; a \neq = 0

Separate the solutions

x_{1} = \frac{- b + b}{2 a}, x_{2} = \frac{- b - b}{2 a}

x = \frac{- b + b}{2 a} : 0

x = \frac{- b - b}{2 a} : - \frac{b}{a}

The solutions to the quadratic equation are:

x = 0, x = - \frac{b}{a}; a \neq = 0

5 x^{2} + 3 x + 6 = 0

16 x^{2} - 32 x + 17 = 0

x^{2} - 5 x = - 8

x, x^{2} + x y + y^{2} = 7

x^{2} - x

What are the solutions to the equation ax^2+bx=0 ?
The solutions to the equation ax^2+bx=0 are x=0,x=-b/a ;\quad a\ne 0
Find the zeros of ax^2+bx=0
The zeros of ax^2+bx=0 are x=0,x=-b/a ;\quad a\ne 0