What are the solutions to the equation solvefor a,c^2=a^2+b^2 ?

The solutions to the equation solvefor a,c^2=a^2+b^2 are a=sqrt(c^2-b^2),a=-sqrt(c^2-b^2)

Find the zeros of solvefor a,c^2=a^2+b^2

The zeros of solvefor a,c^2=a^2+b^2 are a=sqrt(c^2-b^2),a=-sqrt(c^2-b^2)

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solve for

a, c^{2} = a^{2} + b^{2}

a = c^{2} - b^{2}, a = - c^{2} - b^{2}

Solution steps

c^{2} = a^{2} + b^{2}

Switch sides

a^{2} + b^{2} = c^{2}

Move

b^{2}

to the right side

a^{2} = c^{2} - b^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = c^{2} - b^{2}, a = - c^{2} - b^{2}

x, 5 x^{2} - 2 x y + 2 y^{2} - 2 y - 71 = 0

6 x^{2} + 4 x = 0

a, y^{2} + a^{2} = (a + y)^{2} - a (a + 1)

- 4 x^{2} + 6 x - 2 = 0

b, a^{2} + b^{2} = c^{2}

What are the solutions to the equation solvefor a,c^2=a^2+b^2 ?
The solutions to the equation solvefor a,c^2=a^2+b^2 are a=sqrt(c^2-b^2),a=-sqrt(c^2-b^2)
Find the zeros of solvefor a,c^2=a^2+b^2
The zeros of solvefor a,c^2=a^2+b^2 are a=sqrt(c^2-b^2),a=-sqrt(c^2-b^2)