What are the solutions to the equation 5t^2-20t+20=0 ?

The solutions to the equation 5t^2-20t+20=0 are t=2

Find the zeros of 5t^2-20t+20=0

The zeros of 5t^2-20t+20=0 are t=2

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5 t^{2} - 20 t + 20 = 0

t = 2

Solution steps

5 t^{2} - 20 t + 20 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 5 \cdot 20}{2 \cdot 5}

(- 20)^{2} - 4 \cdot 5 \cdot 20 = 0

t_{1, 2} = \frac{- ( - 20 ) \pm 0}{2 \cdot 5}

t = \frac{- ( - 20 )}{2 \cdot 5}

\frac{- ( - 20 )}{2 \cdot 5} = 2

t = 2

The solution to the quadratic equation is:

t = 2

x^{2} + b x + c = 0

3 x^{2} + 5 = 5 x^{2} - 8 x

m^{2} + m = 0

x^{2} + 64 = - 20 x

x^{2} - 2.5 x + 1.5 = 0

What are the solutions to the equation 5t^2-20t+20=0 ?
The solutions to the equation 5t^2-20t+20=0 are t=2
Find the zeros of 5t^2-20t+20=0
The zeros of 5t^2-20t+20=0 are t=2