What are the solutions to the equation ax^2+c=0 ?

The solutions to the equation ax^2+c=0 are x=isqrt(c/a),x=-isqrt(c/a);\quad a\ne 0

Find the zeros of ax^2+c=0

The zeros of ax^2+c=0 are x=isqrt(c/a),x=-isqrt(c/a);\quad a\ne 0

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a x^{2} + c = 0

x = i \frac{c}{a}, x = - i \frac{c}{a}; a \neq = 0

Solution steps

a x^{2} + c = 0

Move

c

to the right side

a x^{2} = - c

Divide both sides by

a; a \neq = 0

x^{2} = - \frac{c}{a}; a \neq = 0

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{c}{a}, x = - - \frac{c}{a}; a \neq = 0

Simplify

- \frac{c}{a} : i \frac{c}{a}

Simplify

- - \frac{c}{a} : - i \frac{c}{a}

x = i \frac{c}{a}, x = - i \frac{c}{a}; a \neq = 0

4 x^{2} - 4 x + 3

2 x^{2} - 12 x + 16 = 0

x^{2} - 5 x + 6 = 0

5 x^{2} - 500 = 0

a, a^{2} = b^{2} + c^{2}

What are the solutions to the equation ax^2+c=0 ?
The solutions to the equation ax^2+c=0 are x=isqrt(c/a),x=-isqrt(c/a);\quad a\ne 0
Find the zeros of ax^2+c=0
The zeros of ax^2+c=0 are x=isqrt(c/a),x=-isqrt(c/a);\quad a\ne 0