What are the solutions to the equation 7x^2+7x-84=0 ?

The solutions to the equation 7x^2+7x-84=0 are x=3,x=-4

Find the zeros of 7x^2+7x-84=0

The zeros of 7x^2+7x-84=0 are x=3,x=-4

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7 x^{2} + 7 x - 84 = 0

x = 3, x = - 4

Solution steps

7 x^{2} + 7 x - 84 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 7 ( - 84 )}{2 \cdot 7}

7^{2} - 4 \cdot 7 (- 84) = 49

x_{1, 2} = \frac{- 7 \pm 49}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 7 + 49}{2 \cdot 7}, x_{2} = \frac{- 7 - 49}{2 \cdot 7}

x = \frac{- 7 + 49}{2 \cdot 7} : 3

x = \frac{- 7 - 49}{2 \cdot 7} : - 4

The solutions to the quadratic equation are:

x = 3, x = - 4

x, x^{2} - x y + y^{2} = 3

4 x^{2} + 29 = - 28 x

(x - 5)^{2} - (x - 6)^{2} = (2 x - 3)^{2} - 118

x^{2} = - 6 x - 9

x, f = x^{2} y

What are the solutions to the equation 7x^2+7x-84=0 ?
The solutions to the equation 7x^2+7x-84=0 are x=3,x=-4
Find the zeros of 7x^2+7x-84=0
The zeros of 7x^2+7x-84=0 are x=3,x=-4