What are the solutions to the equation x^2+98=0 ?

The solutions to the equation x^2+98=0 are x=sqrt(2)*7i,x=-sqrt(2)*7i

Find the zeros of x^2+98=0

The zeros of x^2+98=0 are x=sqrt(2)*7i,x=-sqrt(2)*7i

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x^{2} + 98 = 0

x = 2 \cdot 7 i, x = - 2 \cdot 7 i

Solution steps

x^{2} + 98 = 0

Move

98

to the right side

x^{2} = - 98

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 98, x = - - 98

- 98 = 2 \cdot 7 i

- - 98 = - 2 \cdot 7 i

x = 2 \cdot 7 i, x = - 2 \cdot 7 i

\frac{1}{x - 7} + \frac{1}{x + 2} \geq \frac{2 x}{x ^{2} + x - 2}

4^{1}

T + 3 \frac{T}{2} + \frac{( T + 2 )}{2} T = 4 T^{2}

2 x - 3 (x + 1) \geq 3 x

(n^{4})^{\frac{3}{2}}

What are the solutions to the equation x^2+98=0 ?
The solutions to the equation x^2+98=0 are x=sqrt(2)*7i,x=-sqrt(2)*7i
Find the zeros of x^2+98=0
The zeros of x^2+98=0 are x=sqrt(2)*7i,x=-sqrt(2)*7i