What are the solutions to the equation x^2+4x=7x ?

The solutions to the equation x^2+4x=7x are x=3,x=0

Find the zeros of x^2+4x=7x

The zeros of x^2+4x=7x are x=3,x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 4 x = 7 x

x = 3, x = 0

Solution steps

x^{2} + 4 x = 7 x

Move

7 x

to the left side

x^{2} - 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 0 = 3

x_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 3}{2 \cdot 1}

x = \frac{- ( - 3 ) + 3}{2 \cdot 1} : 3

x = \frac{- ( - 3 ) - 3}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 3, x = 0

x^{2} - 12 x

x^{2} - x - 6 = 0

x^{2} + 9 x + 20 = 0

3 x^{2} - 12 x + 8 = 0

x^{2} - 12 x + 6 = 0

What are the solutions to the equation x^2+4x=7x ?
The solutions to the equation x^2+4x=7x are x=3,x=0
Find the zeros of x^2+4x=7x
The zeros of x^2+4x=7x are x=3,x=0