What are the solutions to the equation 4x^2+29=-12x ?

The solutions to the equation 4x^2+29=-12x are x=-3/2+sqrt(5)i,x=-3/2-sqrt(5)i

Find the zeros of 4x^2+29=-12x

The zeros of 4x^2+29=-12x are x=-3/2+sqrt(5)i,x=-3/2-sqrt(5)i

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4 x^{2} + 29 = - 12 x

x = - \frac{3}{2} + 5 i, x = - \frac{3}{2} - 5 i

Solution steps

4 x^{2} + 29 = - 12 x

Move

12 x

to the left side

4 x^{2} + 29 + 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} + 12 x + 29 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 \cdot 29}{2 \cdot 4}

Simplify

1 2^{2} - 4 \cdot 4 \cdot 29 : 85 i

x_{1, 2} = \frac{- 12 \pm 8 5 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 12 + 8 5 i}{2 \cdot 4}, x_{2} = \frac{- 12 - 8 5 i}{2 \cdot 4}

x = \frac{- 12 + 8 5 i}{2 \cdot 4} : - \frac{3}{2} + 5 i

x = \frac{- 12 - 8 5 i}{2 \cdot 4} : - \frac{3}{2} - 5 i

The solutions to the quadratic equation are:

x = - \frac{3}{2} + 5 i, x = - \frac{3}{2} - 5 i

16 p^{2} - 8 p + 1 = 0

3 x^{2} + 2 x = 1

25 x^{2} + 90 x + 82 = 0

x, z = x^{2}

x^{2} - 20 x + 12 = 0

What are the solutions to the equation 4x^2+29=-12x ?
The solutions to the equation 4x^2+29=-12x are x=-3/2+sqrt(5)i,x=-3/2-sqrt(5)i
Find the zeros of 4x^2+29=-12x
The zeros of 4x^2+29=-12x are x=-3/2+sqrt(5)i,x=-3/2-sqrt(5)i