What are the solutions to the equation x^2+4x-9=5x+3 ?

The solutions to the equation x^2+4x-9=5x+3 are x=4,x=-3

Find the zeros of x^2+4x-9=5x+3

The zeros of x^2+4x-9=5x+3 are x=4,x=-3

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x^{2} + 4 x - 9 = 5 x + 3

x = 4, x = - 3

Solution steps

x^{2} + 4 x - 9 = 5 x + 3

Move

3

to the left side

x^{2} + 4 x - 12 = 5 x

Move

5 x

to the left side

x^{2} - x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 12) = 7

x_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 7}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 7}{2 \cdot 1}

x = \frac{- ( - 1 ) + 7}{2 \cdot 1} : 4

x = \frac{- ( - 1 ) - 7}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 4, x = - 3

q^{2} - 81

3 x - 3 \leq - 9

r^{2} - 10 r + 41 = 0

- 5 v^{2} - 8 v + 4

- x^{2} + 4 x = x^{2} - 2 x

What are the solutions to the equation x^2+4x-9=5x+3 ?
The solutions to the equation x^2+4x-9=5x+3 are x=4,x=-3
Find the zeros of x^2+4x-9=5x+3
The zeros of x^2+4x-9=5x+3 are x=4,x=-3