What are the solutions to the equation -4x^2+9=0 ?

The solutions to the equation -4x^2+9=0 are x= 3/2 ,x=-3/2

Find the zeros of -4x^2+9=0

The zeros of -4x^2+9=0 are x= 3/2 ,x=-3/2

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- 4 x^{2} + 9 = 0

x = \frac{3}{2}, x = - \frac{3}{2}

Decimal Notation

x = 1.5, x = - 1.5

Solution steps

- 4 x^{2} + 9 = 0

Move

9

to the right side

- 4 x^{2} = - 9

Divide both sides by

- 4

x^{2} = \frac{9}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{9}{4}, x = - \frac{9}{4}

\frac{9}{4} = \frac{3}{2}

- \frac{9}{4} = - \frac{3}{2}

x = \frac{3}{2}, x = - \frac{3}{2}

x^{2} - 7 x

\frac{1}{2} x^{2} = 32

- 3 x^{2} - 7 = - 88

2 x^{2} - 6 x + 12 = 0

x^{2} - 2 x + 2

What are the solutions to the equation -4x^2+9=0 ?
The solutions to the equation -4x^2+9=0 are x= 3/2 ,x=-3/2
Find the zeros of -4x^2+9=0
The zeros of -4x^2+9=0 are x= 3/2 ,x=-3/2