What are the solutions to the equation -x^2+x-3=0 ?

The solutions to the equation -x^2+x-3=0 are x= 1/2-i(sqrt(11))/2 ,x= 1/2+i(sqrt(11))/2

Find the zeros of -x^2+x-3=0

The zeros of -x^2+x-3=0 are x= 1/2-i(sqrt(11))/2 ,x= 1/2+i(sqrt(11))/2

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- x^{2} + x - 3 = 0

x = \frac{1}{2} - i \frac{11}{2}, x = \frac{1}{2} + i \frac{11}{2}

Solution steps

- x^{2} + x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 1 ) ( - 3 )}{2 ( - 1 )}

Simplify

1^{2} - 4 (- 1) (- 3) : 11 i

x_{1, 2} = \frac{- 1 \pm 11 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 1 + 11 i}{2 ( - 1 )}, x_{2} = \frac{- 1 - 11 i}{2 ( - 1 )}

x = \frac{- 1 + 11 i}{2 ( - 1 )} : \frac{1}{2} - i \frac{11}{2}

x = \frac{- 1 - 11 i}{2 ( - 1 )} : \frac{1}{2} + i \frac{11}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} - i \frac{11}{2}, x = \frac{1}{2} + i \frac{11}{2}

- x^{2} - 6 x - 7 = 0

3 x^{2} + 9 x - 6 = 0

y^{2} - \frac{1}{16} = 0

\frac{2 x ^{2}}{4} - \frac{x}{6} = \frac{3}{2}

12 x^{2} - 108 x = 0

What are the solutions to the equation -x^2+x-3=0 ?
The solutions to the equation -x^2+x-3=0 are x= 1/2-i(sqrt(11))/2 ,x= 1/2+i(sqrt(11))/2
Find the zeros of -x^2+x-3=0
The zeros of -x^2+x-3=0 are x= 1/2-i(sqrt(11))/2 ,x= 1/2+i(sqrt(11))/2