What are the solutions to the equation 5(x+5)^2-33=2 ?

The solutions to the equation 5(x+5)^2-33=2 are x=sqrt(7)-5,x=-sqrt(7)-5

Find the zeros of 5(x+5)^2-33=2

The zeros of 5(x+5)^2-33=2 are x=sqrt(7)-5,x=-sqrt(7)-5

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5 (x + 5)^{2} - 33 = 2

x = 7 - 5, x = - 7 - 5

Decimal Notation

x = - 2.35424 \dots, x = - 7.64575 \dots

Solution steps

5 (x + 5)^{2} - 33 = 2

Move

33

to the right side

5 (x + 5)^{2} = 35

Divide both sides by

5

(x + 5)^{2} = 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 5 = 7 : x = 7 - 5

Solve

x + 5 = - 7 : x = - 7 - 5

The solutions to the quadratic equation are:

x = 7 - 5, x = - 7 - 5

7 x^{2} + 21 = 0

6 x^{2} - 17 x + 12 = 0

9 x^{2} + 6 x = - 1

5 (x^{2} - 6) + 5 = 5

s^{2} + 2 s + 2

What are the solutions to the equation 5(x+5)^2-33=2 ?
The solutions to the equation 5(x+5)^2-33=2 are x=sqrt(7)-5,x=-sqrt(7)-5
Find the zeros of 5(x+5)^2-33=2
The zeros of 5(x+5)^2-33=2 are x=sqrt(7)-5,x=-sqrt(7)-5