What are the solutions to the equation 5-2x^2=-27 ?

The solutions to the equation 5-2x^2=-27 are x=4,x=-4

Find the zeros of 5-2x^2=-27

The zeros of 5-2x^2=-27 are x=4,x=-4

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5 - 2 x^{2} = - 27

x = 4, x = - 4

Solution steps

5 - 2 x^{2} = - 27

Move

5

to the right side

- 2 x^{2} = - 32

Divide both sides by

- 2

x^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 16, x = - 16

16 = 4

- 16 = - 4

x = 4, x = - 4

4 x^{2} - 20 x = - 29

5 (x - 9)^{2} = 20

y, x^{3} + 4 x^{2} + x y^{2} - 4 y^{2} = 0

3 y^{2} - 11 y + 10 = 0

x, x^{2} + y^{2} + 3 x + y + 10 = 0

What are the solutions to the equation 5-2x^2=-27 ?
The solutions to the equation 5-2x^2=-27 are x=4,x=-4
Find the zeros of 5-2x^2=-27
The zeros of 5-2x^2=-27 are x=4,x=-4