What are the solutions to the equation solvefor a,a^2+7^2=16^2 ?

The solutions to the equation solvefor a,a^2+7^2=16^2 are a=3sqrt(23),a=-3sqrt(23)

Find the zeros of solvefor a,a^2+7^2=16^2

The zeros of solvefor a,a^2+7^2=16^2 are a=3sqrt(23),a=-3sqrt(23)

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solve for

a, a^{2} + 7^{2} = 1 6^{2}

a = 323, a = - 323

Decimal Notation

a = 14.38749 \dots, a = - 14.38749 \dots

Solution steps

a^{2} + 7^{2} = 1 6^{2}

Move

7^{2}

to the right side

a^{2} = 207

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = 207, a = - 207

207 = 323

- 207 = - 323

a = 323, a = - 323

2 (x + 3)^{2} = 18

7 x^{2} + 84 = 0

8 - x^{2} = 7

4 x^{2} + 52 = 4

y, y^{2} (4 - x) = x^{3}

What are the solutions to the equation solvefor a,a^2+7^2=16^2 ?
The solutions to the equation solvefor a,a^2+7^2=16^2 are a=3sqrt(23),a=-3sqrt(23)
Find the zeros of solvefor a,a^2+7^2=16^2
The zeros of solvefor a,a^2+7^2=16^2 are a=3sqrt(23),a=-3sqrt(23)