What are the solutions to the equation 4x^2+13=-20x ?

The solutions to the equation 4x^2+13=-20x are x=(-5+2sqrt(3))/2 ,x=-(5+2sqrt(3))/2

Find the zeros of 4x^2+13=-20x

The zeros of 4x^2+13=-20x are x=(-5+2sqrt(3))/2 ,x=-(5+2sqrt(3))/2

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4 x^{2} + 13 = - 20 x

x = \frac{- 5 + 2 3}{2}, x = - \frac{5 + 2 3}{2}

Decimal Notation

x = - 0.76794 \dots, x = - 4.23205 \dots

Solution steps

4 x^{2} + 13 = - 20 x

Move

20 x

to the left side

4 x^{2} + 13 + 20 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} + 20 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 4 \cdot 13}{2 \cdot 4}

2 0^{2} - 4 \cdot 4 \cdot 13 = 83

x_{1, 2} = \frac{- 20 \pm 8 3}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 20 + 8 3}{2 \cdot 4}, x_{2} = \frac{- 20 - 8 3}{2 \cdot 4}

x = \frac{- 20 + 8 3}{2 \cdot 4} : \frac{- 5 + 2 3}{2}

x = \frac{- 20 - 8 3}{2 \cdot 4} : - \frac{5 + 2 3}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 2 3}{2}, x = - \frac{5 + 2 3}{2}

4 x^{2} - 13 x + 7 = 4

3 (x + 3)^{2} - 46 = 17

6 x^{2} + 108 = 0

19 - 3 x^{2} = 1

12 x^{2} - 48 x + 36 = 0

What are the solutions to the equation 4x^2+13=-20x ?
The solutions to the equation 4x^2+13=-20x are x=(-5+2sqrt(3))/2 ,x=-(5+2sqrt(3))/2
Find the zeros of 4x^2+13=-20x
The zeros of 4x^2+13=-20x are x=(-5+2sqrt(3))/2 ,x=-(5+2sqrt(3))/2