What are the solutions to the equation x^2-3/2 x-1=0 ?

The solutions to the equation x^2-3/2 x-1=0 are x=2,x=-1/2

Find the zeros of x^2-3/2 x-1=0

The zeros of x^2-3/2 x-1=0 are x=2,x=-1/2

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x^{2} - \frac{3}{2} x - 1 = 0

x = 2, x = - \frac{1}{2}

Decimal Notation

x = 2, x = - 0.5

Solution steps

x^{2} - \frac{3}{2} x - 1 = 0

Multiply both sides by

2

2 x^{2} - 3 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 ( - 2 )}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 (- 2) = 5

x_{1, 2} = \frac{- ( - 3 ) \pm 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 5}{2 \cdot 2}, x_{2} = \frac{- ( - 3 ) - 5}{2 \cdot 2}

x = \frac{- ( - 3 ) + 5}{2 \cdot 2} : 2

x = \frac{- ( - 3 ) - 5}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = 2, x = - \frac{1}{2}

x^{2} - 6 x + 10

2 - x^{2} = - 11

(x - 3) (x + 5) = 0

x^{2} - 4 x = 7

x^{2} - 14 x

What are the solutions to the equation x^2-3/2 x-1=0 ?
The solutions to the equation x^2-3/2 x-1=0 are x=2,x=-1/2
Find the zeros of x^2-3/2 x-1=0
The zeros of x^2-3/2 x-1=0 are x=2,x=-1/2