What are the solutions to the equation 2w^2-16w=12w-48 ?

The solutions to the equation 2w^2-16w=12w-48 are w=12,w=2

Find the zeros of 2w^2-16w=12w-48

The zeros of 2w^2-16w=12w-48 are w=12,w=2

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2 w^{2} - 16 w = 12 w - 48

w = 12, w = 2

Solution steps

2 w^{2} - 16 w = 12 w - 48

Move

48

to the left side

2 w^{2} - 16 w + 48 = 12 w

Move

12 w

to the left side

2 w^{2} - 28 w + 48 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 \cdot 2 \cdot 48}{2 \cdot 2}

(- 28)^{2} - 4 \cdot 2 \cdot 48 = 20

w_{1, 2} = \frac{- ( - 28 ) \pm 20}{2 \cdot 2}

Separate the solutions

w_{1} = \frac{- ( - 28 ) + 20}{2 \cdot 2}, w_{2} = \frac{- ( - 28 ) - 20}{2 \cdot 2}

w = \frac{- ( - 28 ) + 20}{2 \cdot 2} : 12

w = \frac{- ( - 28 ) - 20}{2 \cdot 2} : 2

The solutions to the quadratic equation are:

w = 12, w = 2

1 3^{2} = 1 2^{2} + x^{2}

0 = 9 x^{2} - 10

x^{2} + 6 x - 18 = 0

x^{2} + 8 x + 3

x, x^{2} + y^{2} = z^{2}

What are the solutions to the equation 2w^2-16w=12w-48 ?
The solutions to the equation 2w^2-16w=12w-48 are w=12,w=2
Find the zeros of 2w^2-16w=12w-48
The zeros of 2w^2-16w=12w-48 are w=12,w=2