What are the solutions to the equation -2x^2+6x-3=0 ?

The solutions to the equation -2x^2+6x-3=0 are x=(3-sqrt(3))/2 ,x=(3+sqrt(3))/2

Find the zeros of -2x^2+6x-3=0

The zeros of -2x^2+6x-3=0 are x=(3-sqrt(3))/2 ,x=(3+sqrt(3))/2

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- 2 x^{2} + 6 x - 3 = 0

x = \frac{3 - 3}{2}, x = \frac{3 + 3}{2}

Decimal Notation

x = 0.63397 \dots, x = 2.36602 \dots

Solution steps

- 2 x^{2} + 6 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 2 ) ( - 3 )}{2 ( - 2 )}

6^{2} - 4 (- 2) (- 3) = 23

x_{1, 2} = \frac{- 6 \pm 2 3}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 3}{2 ( - 2 )}, x_{2} = \frac{- 6 - 2 3}{2 ( - 2 )}

x = \frac{- 6 + 2 3}{2 ( - 2 )} : \frac{3 - 3}{2}

x = \frac{- 6 - 2 3}{2 ( - 2 )} : \frac{3 + 3}{2}

The solutions to the quadratic equation are:

x = \frac{3 - 3}{2}, x = \frac{3 + 3}{2}

x, x^{2} - 9 y^{2} + 2 x - 54 y - 80 = 0

x^{2} - 91 x + c = 0

x^{2} + 4.5 x + 5 = 0

x^{2} + 7 x - 2 = 0

3 x^{2} + 8 x - 11 = 0

What are the solutions to the equation -2x^2+6x-3=0 ?
The solutions to the equation -2x^2+6x-3=0 are x=(3-sqrt(3))/2 ,x=(3+sqrt(3))/2
Find the zeros of -2x^2+6x-3=0
The zeros of -2x^2+6x-3=0 are x=(3-sqrt(3))/2 ,x=(3+sqrt(3))/2