What are the solutions to the equation 5r^2-20r+15=0 ?

The solutions to the equation 5r^2-20r+15=0 are r=3,r=1

Find the zeros of 5r^2-20r+15=0

The zeros of 5r^2-20r+15=0 are r=3,r=1

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5 r^{2} - 20 r + 15 = 0

r = 3, r = 1

Solution steps

5 r^{2} - 20 r + 15 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 5 \cdot 15}{2 \cdot 5}

(- 20)^{2} - 4 \cdot 5 \cdot 15 = 10

r_{1, 2} = \frac{- ( - 20 ) \pm 10}{2 \cdot 5}

Separate the solutions

r_{1} = \frac{- ( - 20 ) + 10}{2 \cdot 5}, r_{2} = \frac{- ( - 20 ) - 10}{2 \cdot 5}

r = \frac{- ( - 20 ) + 10}{2 \cdot 5} : 3

r = \frac{- ( - 20 ) - 10}{2 \cdot 5} : 1

The solutions to the quadratic equation are:

r = 3, r = 1

(1 - k) x^{2} - (k + 1) x - 2 = 0

(x + 2) (x - 3) = 6

x, x^{2} y + x y^{2} = 6

4 x^{2} + 2 = 38

- 6 x^{2} + 12 x = 7

What are the solutions to the equation 5r^2-20r+15=0 ?
The solutions to the equation 5r^2-20r+15=0 are r=3,r=1
Find the zeros of 5r^2-20r+15=0
The zeros of 5r^2-20r+15=0 are r=3,r=1