What are the solutions to the equation 36x=13+36x^2 ?

The solutions to the equation 36x=13+36x^2 are x= 1/2+i 1/3 ,x= 1/2-i 1/3

Find the zeros of 36x=13+36x^2

The zeros of 36x=13+36x^2 are x= 1/2+i 1/3 ,x= 1/2-i 1/3

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36 x = 13 + 36 x^{2}

x = \frac{1}{2} + i \frac{1}{3}, x = \frac{1}{2} - i \frac{1}{3}

Solution steps

36 x = 13 + 36 x^{2}

Switch sides

13 + 36 x^{2} = 36 x

Move

36 x

to the left side

13 + 36 x^{2} - 36 x = 0

Write in the standard form

a x^{2} + b x + c = 0

36 x^{2} - 36 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 36 \cdot 13}{2 \cdot 36}

Simplify

(- 36)^{2} - 4 \cdot 36 \cdot 13 : 24 i

x_{1, 2} = \frac{- ( - 36 ) \pm 24 i}{2 \cdot 36}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 24 i}{2 \cdot 36}, x_{2} = \frac{- ( - 36 ) - 24 i}{2 \cdot 36}

x = \frac{- ( - 36 ) + 24 i}{2 \cdot 36} : \frac{1}{2} + i \frac{1}{3}

x = \frac{- ( - 36 ) - 24 i}{2 \cdot 36} : \frac{1}{2} - i \frac{1}{3}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{1}{3}, x = \frac{1}{2} - i \frac{1}{3}

w (w - 35) = 0

x^{2} - 5 x - 6 = 0

x^{2} + 16 x

4 x^{2} - 36 x = - 85

5 x^{2} + 2 x - 1 = 0

What are the solutions to the equation 36x=13+36x^2 ?
The solutions to the equation 36x=13+36x^2 are x= 1/2+i 1/3 ,x= 1/2-i 1/3
Find the zeros of 36x=13+36x^2
The zeros of 36x=13+36x^2 are x= 1/2+i 1/3 ,x= 1/2-i 1/3