What are the solutions to the equation 2x^2+11=131 ?

The solutions to the equation 2x^2+11=131 are x=2sqrt(15),x=-2sqrt(15)

Find the zeros of 2x^2+11=131

The zeros of 2x^2+11=131 are x=2sqrt(15),x=-2sqrt(15)

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2 x^{2} + 11 = 131

x = 215, x = - 215

Decimal Notation

x = 7.74596 \dots, x = - 7.74596 \dots

Solution steps

2 x^{2} + 11 = 131

Move

11

to the right side

2 x^{2} = 120

Divide both sides by

2

x^{2} = 60

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 60, x = - 60

60 = 215

- 60 = - 215

x = 215, x = - 215

w^{2} - \frac{1}{15} w = \frac{2}{15}

x^{2} + 5 x

x, y^{3} = x^{2}

(2 x + 4)^{2} = 100

x^{2} + 8 x + 16 = 64

What are the solutions to the equation 2x^2+11=131 ?
The solutions to the equation 2x^2+11=131 are x=2sqrt(15),x=-2sqrt(15)
Find the zeros of 2x^2+11=131
The zeros of 2x^2+11=131 are x=2sqrt(15),x=-2sqrt(15)