What are the solutions to the equation -3x^2+x-3=0 ?

The solutions to the equation -3x^2+x-3=0 are x= 1/6-i(sqrt(35))/6 ,x= 1/6+i(sqrt(35))/6

Find the zeros of -3x^2+x-3=0

The zeros of -3x^2+x-3=0 are x= 1/6-i(sqrt(35))/6 ,x= 1/6+i(sqrt(35))/6

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- 3 x^{2} + x - 3 = 0

x = \frac{1}{6} - i \frac{35}{6}, x = \frac{1}{6} + i \frac{35}{6}

Solution steps

- 3 x^{2} + x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 3 ) ( - 3 )}{2 ( - 3 )}

Simplify

1^{2} - 4 (- 3) (- 3) : 35 i

x_{1, 2} = \frac{- 1 \pm 35 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 1 + 35 i}{2 ( - 3 )}, x_{2} = \frac{- 1 - 35 i}{2 ( - 3 )}

x = \frac{- 1 + 35 i}{2 ( - 3 )} : \frac{1}{6} - i \frac{35}{6}

x = \frac{- 1 - 35 i}{2 ( - 3 )} : \frac{1}{6} + i \frac{35}{6}

The solutions to the quadratic equation are:

x = \frac{1}{6} - i \frac{35}{6}, x = \frac{1}{6} + i \frac{35}{6}

(z - 6)^{2} = 25

6 x^{2} + 10 x - 4 = 0

x^{2} - 20 x + 12 = 0

x^{2} - 16 x + 55 = 0

m^{2} + 2 m = 0

What are the solutions to the equation -3x^2+x-3=0 ?
The solutions to the equation -3x^2+x-3=0 are x= 1/6-i(sqrt(35))/6 ,x= 1/6+i(sqrt(35))/6
Find the zeros of -3x^2+x-3=0
The zeros of -3x^2+x-3=0 are x= 1/6-i(sqrt(35))/6 ,x= 1/6+i(sqrt(35))/6