What are the solutions to the equation (x+7)^2-23=34 ?

The solutions to the equation (x+7)^2-23=34 are x=sqrt(57)-7,x=-sqrt(57)-7

Find the zeros of (x+7)^2-23=34

The zeros of (x+7)^2-23=34 are x=sqrt(57)-7,x=-sqrt(57)-7

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(x + 7)^{2} - 23 = 34

x = 57 - 7, x = - 57 - 7

Decimal Notation

x = 0.54983 \dots, x = - 14.54983 \dots

Solution steps

(x + 7)^{2} - 23 = 34

Move

23

to the right side

(x + 7)^{2} = 57

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 7 = 57 : x = 57 - 7

Solve

x + 7 = - 57 : x = - 57 - 7

The solutions to the quadratic equation are:

x = 57 - 7, x = - 57 - 7

5 x^{2} - 11 = 234

4 x^{2} + 4 x - 9 = 0

x^{2} = 3 x + 15

r^{2} - 4 = 0

11 + 19 + 27 + (8 n + 3) = n (4 n + 7)

What are the solutions to the equation (x+7)^2-23=34 ?
The solutions to the equation (x+7)^2-23=34 are x=sqrt(57)-7,x=-sqrt(57)-7
Find the zeros of (x+7)^2-23=34
The zeros of (x+7)^2-23=34 are x=sqrt(57)-7,x=-sqrt(57)-7