What are the solutions to the equation m^2+10m+21=0 ?

The solutions to the equation m^2+10m+21=0 are m=-3,m=-7

Find the zeros of m^2+10m+21=0

The zeros of m^2+10m+21=0 are m=-3,m=-7

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m^{2} + 10 m + 21 = 0

m = - 3, m = - 7

Solution steps

m^{2} + 10 m + 21 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 21}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 21 = 4

m_{1, 2} = \frac{- 10 \pm 4}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 10 + 4}{2 \cdot 1}, m_{2} = \frac{- 10 - 4}{2 \cdot 1}

m = \frac{- 10 + 4}{2 \cdot 1} : - 3

m = \frac{- 10 - 4}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

m = - 3, m = - 7

x^{2} - 5 x + 6 = 0

x^{2} + 18 x

6 x^{2} - 2 = 0

2 (x^{2} + 5) - 7 = 7

x, x^{2} + 1 = 0

What are the solutions to the equation m^2+10m+21=0 ?
The solutions to the equation m^2+10m+21=0 are m=-3,m=-7
Find the zeros of m^2+10m+21=0
The zeros of m^2+10m+21=0 are m=-3,m=-7