What are the solutions to the equation (x-9)^2+26=31 ?

The solutions to the equation (x-9)^2+26=31 are x=sqrt(5)+9,x=-sqrt(5)+9

Find the zeros of (x-9)^2+26=31

The zeros of (x-9)^2+26=31 are x=sqrt(5)+9,x=-sqrt(5)+9

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(x - 9)^{2} + 26 = 31

x = 5 + 9, x = - 5 + 9

Decimal Notation

x = 11.23606 \dots, x = 6.76393 \dots

Solution steps

(x - 9)^{2} + 26 = 31

Move

26

to the right side

(x - 9)^{2} = 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 9 = 5 : x = 5 + 9

Solve

x - 9 = - 5 : x = - 5 + 9

The solutions to the quadratic equation are:

x = 5 + 9, x = - 5 + 9

r, A = 4 π r^{2}

16 - 3 x^{2} = 13

1 3^{2} = 5^{2} + x^{2}

x, x^{2} + y^{2} + z^{2} = 16

6 x^{2} - 11 x + 6 = - 4 x + 4

What are the solutions to the equation (x-9)^2+26=31 ?
The solutions to the equation (x-9)^2+26=31 are x=sqrt(5)+9,x=-sqrt(5)+9
Find the zeros of (x-9)^2+26=31
The zeros of (x-9)^2+26=31 are x=sqrt(5)+9,x=-sqrt(5)+9