What are the solutions to the equation 4x^2+89=36x ?

The solutions to the equation 4x^2+89=36x are x= 9/2+sqrt(2)i,x= 9/2-sqrt(2)i

Find the zeros of 4x^2+89=36x

The zeros of 4x^2+89=36x are x= 9/2+sqrt(2)i,x= 9/2-sqrt(2)i

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4 x^{2} + 89 = 36 x

x = \frac{9}{2} + 2 i, x = \frac{9}{2} - 2 i

Solution steps

4 x^{2} + 89 = 36 x

Move

36 x

to the left side

4 x^{2} + 89 - 36 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 36 x + 89 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 4 \cdot 89}{2 \cdot 4}

Simplify

(- 36)^{2} - 4 \cdot 4 \cdot 89 : 82 i

x_{1, 2} = \frac{- ( - 36 ) \pm 8 2 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 8 2 i}{2 \cdot 4}, x_{2} = \frac{- ( - 36 ) - 8 2 i}{2 \cdot 4}

x = \frac{- ( - 36 ) + 8 2 i}{2 \cdot 4} : \frac{9}{2} + 2 i

x = \frac{- ( - 36 ) - 8 2 i}{2 \cdot 4} : \frac{9}{2} - 2 i

The solutions to the quadratic equation are:

x = \frac{9}{2} + 2 i, x = \frac{9}{2} - 2 i

x^{2} + 14 x = - 45

5 x^{2} = 3 x + 2

4 (x - 2)^{2} = 16

- x^{2} + 5 = 0

2 x^{2} + 14 = - 84

What are the solutions to the equation 4x^2+89=36x ?
The solutions to the equation 4x^2+89=36x are x= 9/2+sqrt(2)i,x= 9/2-sqrt(2)i
Find the zeros of 4x^2+89=36x
The zeros of 4x^2+89=36x are x= 9/2+sqrt(2)i,x= 9/2-sqrt(2)i